Calculating Area with Stokes Theorem
Most of us learn to calculate areas using formulas drilled into memory: length times width for rectangles, πr² for circles. Let’s see another approach hiding in vector calculus – one that works for any shape, no matter how irregular. Enter Stokes’ theorem.
§The Trick
Stokes’ theorem relates a line integral around a closed curve to a surface integral over the region it encloses. For area calculation, we can exploit this relationship with a clever choice of vector field.
The key insight: we need a field F whose curl equals 1. Why? Because Stokes’ theorem tells us:
∮C F · dr = ∫∫R (∇ × F) · n dA
For planar regions, the curl ∇ × F = (∂F₂/∂x - ∂F₁/∂y)k points perpendicular to the plane, so this becomes:
∮C F · dr = ∫∫R (∂F₂/∂x - ∂F₁/∂y) dA
If we make (∂F₂/∂x - ∂F₁/∂y) = 1, the right side becomes ∫∫R 1 dA, which is just the area. Any F satisfying this works—common choices include F = (0, x), F = (-y, 0), or F = (-y/2, x/2). Let’s see them in action.
§Example 1: The Unit Square
Consider a square with vertices at (0,0), (1,0), (1,1), and (0,1). We’ll traverse the boundary counterclockwise.
Using F = (0, x), the line integral ∮C x dy becomes:
- Bottom edge (y=0, dy=0): contributes 0
- Right edge (x=1, y: 0→1): ∫₀¹ 1 dy = 1
- Top edge (y=1, dy=0): contributes 0
- Left edge (x=0, y: 1→0): ∫₁⁰ 0 dy = 0
Total: 1 square unit. Exactly what we expected.
§Example 2: The Unit Circle
Now for something curvier. The unit circle x² + y² = 1 can be parameterized as r(t) = (cos t, sin t) for t ∈ [0, 2π].
This time, let’s use the symmetric field: F = (-y/2, x/2). The line integral ∮C (-y/2 dx + x/2 dy) becomes:
∮C (-y/2 dx + x/2 dy) = ∫₀²π (-sin(t)/2 · (-sin t) + cos(t)/2 · cos t) dt
= ∫₀²π (sin²(t)/2 + cos²(t)/2) dt = ∫₀²π (sin²(t) + cos²(t))/2 dt
Using the identity sin²(t) + cos²(t) = 1:
∫₀²π 1/2 dt = π
Again, π square units—same answer, even cleaner calculation. The symmetric choice F = (-y/2, x/2) often simplifies circular and elliptical boundaries.
§Why This Matters
With this technique, we can calculate areas of arbitrary shape.